Chemistry, asked by naitik7153, 1 month ago

If 10g of salt is added to 50 g of water, what is the mass of the solution?

Answers

Answered by samruddhideshmukh098
1

Answer:

Here salt is solute and is 10g , whereas water is solvent and has weight of 100g. So the total mass of the Solution will be 100g + 10g = 110g

Answered by shuklagarima325
0

Answer:

We need to find the Mass% of the solution , that contains 10g of salt mixed with 100g of water. Mass % can be calculated by dividing the mass of solute divided by total mass of solution ( solute + solvent) times 100 .

Here salt is solute and is 10g , whereas water is solvent and has weight of 100g. So the total mass of the Solution will be 100g + 10g = 110g . Now let's Calculate the mass percentage .

\begin{gathered}\sf\dashrightarrow Mass\% =\dfrac{Mass_{(Solute)}}{Mass_{(Solution)}}\times 100 \\\\\sf\dashrightarrow Mass\% = \dfrac{ 10g}{100g + 10g}\times 100 \\\\\sf\dashrightarrow Mass\% = \dfrac{ 10g}{110g}\times 100 \\\\\sf\dashrightarrow Mass\% = \dfrac{ 100}{11}\% \\\\\sf\dashrightarrow \boxed{\pink{\sf Mass\% = 9.09 \approx 9\% }}\end{gathered}

⇢Mass%=

Mass

(Solution)

Mass

(Solute)

×100

⇢Mass%=

100g+10g

10g

×100

⇢Mass%=

110g

10g

×100

⇢Mass%=

11

100

%

Mass%=9.09≈9%

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