Question

If 10J of work is done in moving 5C of charge then voltage is​

Answer 1

Answer:

$\boxed{\mathfrak{Potential \ difference \ (\Delta V) = 50 \ V}}$

Given:

Work done (W) = 10J

Charge (Q) = 5 C

To Find:

Potential difference (ΔV)

Explanation:

Formula:

$\boxed{ \bold{ \sf Work \: done \: (W) = \frac{Potential \: difference \: (\Delta V)}{Charge \: (Q)} }}$

$\sf \implies \Delta V = QW$

Substituting value of Q & W in the equation:

$\sf \implies \Delta V = 5 \times 10 \\ \\ \sf \implies \Delta V = 50 \: V$

$\therefore$

Potential difference (ΔV) = 50 V

Answer 2

ᎯᏁᏕᏯᎬᏒ

Work done = 10J

Quantity of Charge = 5C

$\boxed{ \rm{Voltage (V) = \frac{Work~done(W)}{Quantity ~of ~Charge(Q)} }}$

$\rm V = \frac{10~J}{5~C}$

$\rm {\red{V = 2~Volts}}$