Question

If 10th term and the 18th term of an A.P. are 25 and
41 respectively, then find the 38th term. ​

Answer 1

Answer:

81

Step-by-step explanation:

let the first term and common difference is a and d ,

then tn=a+(n-1)d

t10=25

a+9d=25. equation 1

t18=41

a+17d=41 equation 2

by solving 1 and 2 we get

d=2 and a=7

t38= 7 + 37×2=81

Answer 2

Answer:

A10=25

a+9d=25(eq1)

A18=41

a+17d=41(eq2)

subtracing eq1from2

a+17d=41

a+9d=25

so,8d=16

d=2

putting d=2 in1

a+18=25

a=7

so,A38 =a+37d

= 7+37*2

=7+74

81

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