if 10th term of an ap is 13 term find the sum of 19term
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Answer:
sorry but couldn't understand what is this ap
Step-by-step explanation:
If the 10th term of an AP is 13 then what will the sum of 19 terms be?
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For the arithmetic progression a,a+b,a+2b,…,a+nb,… , with 10th term equal to 13:
the 9 terms preceding the 10th term would be (in reverse order) 13−b,13−2b,…,13−9b , and
the 9 terms following the 10th term would be 13+b,13+2b,…,13+9b .
Therefore, the sum of the first 19 terms would be
13+(13−b)+(13−2b)+(13−3b)+⋯+(13−9b)+(13+b)+(13+2b)+(13+3b)+⋯+(13+9b)=19⋅13=247
If the 10th term of an AP is 13 then what will the sum of 19 terms be?
If the 5th term of an AP is 19 and the sum of the first 5th term is 65, what is the AP?
In an A.P., if the 12th term is -13 and the the sum of the first 4 terms is 24, what is the sum of the first 10 terms?
What is the 12th term of 13, 16, 19, 22?
What is the 10th term of AP: 2, 7, 12?
If the 12th term of an AP is -13 and the sum of the first four term is 24 what is the sum of first 10 term?
In an A.P., uₙ = a + (n-1)d
u₁₀ = 13
a + 9d = 13
Sₙ = n/2 {2a + (n-1)d}
S₁₉ = 19/2 {2a + 18d}
= 19 {a + 9d}
= 19 {13}
= 247
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