If 10th term of an apis 47 and the first term is 2,then find the sum of its 15 terms
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first term a = 2
let common difference = d
Tn = a + (n-1)d
47 = 2 + (10-1)d
d = 5
Sn = n[2a + (n-1)d]/2
S15 = 15[2*2 + 14*5]/2
S15 = 15*37 = 555
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