Question

if 10th term of ap is 52 and 17th term is 20 more than its 13th term ​

Answer 1

Answer:

a10=52

a17=20+a13

Step-by-step explanation:

a10=52

a+9d=52.......... 1}

a17=20+a13

a+16d=20+a+12d

a+16d-a-12d=20

here 'a' cancelled..

16d-12d=20

4d=20

d=20/4

d=5........

from eq....1}

a+9d=52

a+9(5) =52

a+45=52

a=52-45

a=7.......

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Answer 2

Given:-

• 10th term = 52

• 17th term = 20 more than 13th term.

To Find:-

• Find the Ap.

Solution:-

According to the Question

General form of 10th term = a +(10-1)d here d is common difference.

→ a+9d = 52 .............................(i)

and it is also given that 17th term is 20 more than 13th term

General form of 17th term = a + (17-1)d = a +16d

→ 17th = 20 + a + (13-1)d

→ a +16d = 20 + a + 12d

→ 16d -12d = 20

→ 4d = 20

→ d = 20/4

→ d = 5

The common difference in given no.is 5

From Equation (i)

→ a +9d = 52

Put the value of d = 5

→ a +9×5 = 52

→ a +45 = 52

→ a = 52-45

→ a = 7

Now , AP = 7 , 7+5 , 12 + 5 , 17+5

=. 7 , 12 , 17 , 21

Therefore, the AP are 7, 12, 17 , 21