Question

if 10x^2-23xy+9y^2=0 find x:y

Answer 1

10x^-(18+5)xy+9y^2
10x^2-18xy-5xy+9y^2
10x^2-5xy-18xy+9y^2
5x(2x-y)-2y(2x-y)
(2x-y)(5x-2)=0
5x=2=>x=2/5
2x=y=>y=4/5
x:y=2:5

Answer 2

Answer:

(9:5) or (1 : 2)

Step-by-step explanation:

Given,

10x^2-23xy+9y^2=0

=>10x^2-5xy-18xy+9y^2=0

=>5x(2x-1y)-9y(2x-1y)=0

=>(2x-y)(5x-9y)=0

2x-y=0 (or) 5x-9y=0

2x=1y 5x=9y

x/y=1/2 x/y=9/5

==> x : y = 1:2 or 9:5

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