Math, asked by ananya2016rocks, 11 months ago

if √11-1/√11-1= a-b√11 then find the value of a and b​

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Answers

Answered by Saby123
33

Solution :

LHS :

> [√11 - 1 ]/[ √11 + 1]

> [√11 - 1 ]/[ √11 + 1] × [ √11 - 1]/[ √11 - 1]

> [√11 - 1]²/( 10 )

> [ 11 + 1 - 2√11 ]/10

> [ 12 - 2√11 ]/10

> 6/5 - √11/5

Hence

a = 6/5

b = 1/5 .

This is the required answer .

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Answered by Anonymous
93

Answer

given \:  \\  \\  \frac{ \sqrt{11} - 1 }{ \sqrt{11} + 1 }  = a - b \sqrt{11}  \\  \\ multiply \: nr \: and \: dr \: by \:   \: \sqrt{11}  - 1 \\  \\  \frac{ \sqrt{11}  - 1}{ \sqrt{11} + 1 }  \times  \frac{ \sqrt{11} - 1 }{ \sqrt{11} - 1 }  = a - b \sqrt{11}  \\  \\  \frac{ (\sqrt{11}  - 1) {}^{2} }{ (\sqrt{11}) {}^{2}  - 1 {}^{2}  }  = a - b \sqrt{11}  \\  \\  \frac{12 - 2 \sqrt{11} }{10}  = a - b \sqrt{11}  \\  \\  \frac{6 -  \sqrt{11} }{5}  = a - b \sqrt{11}  \\  \\  \frac{6}{5}  -   \frac{ \sqrt{11} }{5}  = a - b \sqrt{11}  \\  \\ now \: compare \: coffecient \:  \: of \: a \: and \: b \\  \\ a =  \frac{6}{5}  \:  \: and \:  \: b =  \frac{1}{5}

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