Question

if 11/7-3 unde root 3 =a+b under root 3 then find value of a-b ​

Answer 1

Answer: hi friend !

$lhs = (5+2√3)/(7+4√3)= [(5+2√3)(7-4√3)]/[(7-4√3)(7+4√3)]=[35-20√3+14√3-24]/[7²-(4√3)²]=[11-6√3]/[49-48]=11-6√3therefore11-6√3 = a+b√3compare both sidesa= 11, b= -6$

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