Question

If 11% of a number exceeds 7% of the same by 18 , then the number is

Answer 1

Let the number be x.

11% of x = 7% of x + 18.....(given condition)
$\frac{11}{100} x = \frac{7}{100}x + 18$

$\frac{11x}{100} = \frac{7x}{100} + 18$

$\frac{11x}{100} - \frac{7x}{100} = 18$

$\frac{11x - 7x}{100} = 18$

$\frac{4x}{100} = 18$

$4x = 18 \times 100$

$4x = 1800$

$x = \frac{1800}{4}$

$x =450$
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Therefore ,
The number is 450.
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$hope \: this \: helps$

Answer 2

Heya ✋

Let see your answer !!!

Let the required number be x. Then,

11 % of x = (7 % of x) + 18

=> 11/100 × x = (7/100 × x) + 18

=> 11x/100 = 7x/100 + 18

=> 11x/100 - 7x/100 = 18

=> 11x - 7x/100 = 18

=> 4x/100 = 18

=> x/25 = 18

=> x = 18 × 25

=> x = 450

Hence , the required number is 450.



Thanks :))))