Question

If 11 pens and 19 pencils together cost ₹502; while 19 pens and 11 pencils together cost
758, how much 3 pens and 6 pencils cost together?

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Answer 1

Step-by-step explanation:

let cost of 1 pen be x

and cost of 1 pencil be y

therefore, 11 x + 19y = 502 ....1

19x + 11y = 758 .....2

from eq. 1 we get,

y = 502 - 11x/19

substituting it in eq.2

19x + 11× 502 - 11x /19 = 758,

758= 19x + 5522 - 121x / 19

multiplying 19..

14402 =361x + 5522 -121 x

14402 -5522 = 361x - 121x

8880 = 240x

x = 8880/ 240 =37

y = 502 - 11×37 /19 = 5

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Answer 2

Answer:

140 rupees

Step-by-step explanation:

Let the cost of 1 pen = x

Let the cost of 1 pencil= y

According to the given conditions, the equations will be:-

11x+19y=502 (1)

19x+11y=758 (2)

By elimination method:

Multiplying equation (1) by 19 and equation (2) by 11, we get:

209x+361y=9538 (3)

209x+ 121y=8338 (4)

Subtracting equation (4) from equation (3)

209x+361y=9538

209x+ 121y=8338

- - -

240y=1200

=> y= 1200/240

=> y= 5

Substituting the value of y in equation (1), we get:

11x+19(5)=502

=> 11x= 502-95

=> x= 407/11

=> x= 37

Therefore the cost of 1 pen is 37 and the cost of 1 pencil is 5

Now, for 3 pens and 6 pencils,

3x+6y=?

3(37)+6(5)

= 111+30

= 140

Therefore the cost of 3 pens and 6 pencils is 140 rupees.

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