if 11 x+13y=7.4 and 13x+11y=7.0 then 10 x+y=7
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13x+11y=70−−−eqn(1)
11x+13y=74−−−eqn(2)
Multiplying eqn(1) with 11
11(13x+11y)=11×70
⟹143x+121y=770−−−eqn(3)
Multiplying eqn(2) with 13
13(11x+13y)=13×74
143x+169y=962−−−eqn(4)
Subtracting eqn(3) from eqn(4) we get,
48y=192 ⟹y=4
Now let us eliminate y.
Multiplying eqn(1) with 13 then we get,
169x+143y=910−−−eqn(5)
Multiplying eqn(2) with 11, we get
121x+143y=814−−−−eqn(6)
Subtracting eqn(6) from eqn(5),we get x=2
So x=2 and y=4 is our solution
hope it helps you!
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