Question

If 110 g. of copper sulphate is present in 550 g. of solution, calcu concentration of solution.​

Answer 1

Answer:

Your answer

Hope it helps you

Answer 2

Answer:

Molality, m = W × 1000/ M × w.

Where, W = weight of CuSO4 taken = 110g

m = Molar mass of CuSO4 = 160g

w. = Weight of solvent taken in g (550g - 110g = 440g)

So, m = 110 × 1000 / 160 × 440

m = 1.56 m

hope this will help you