If 110g of copper sulphate is present in 550g of solution,calculate the concentration of solution.
Answers
Answered by
244
Mass by mass percentage of a solution = [(Mass of solute) / (Mass of solution)] X 100
Here, mass of solute ( cuSo4) = 110g
Mass of solution = 550 g
Therefore mass by mass percentage of solution = (110 X 100) / 550
= 20%
Hence, the concentration of the solution is 20%.
Here, mass of solute ( cuSo4) = 110g
Mass of solution = 550 g
Therefore mass by mass percentage of solution = (110 X 100) / 550
= 20%
Hence, the concentration of the solution is 20%.
Answered by
108
Hi friend,
The concentration of solution is 20% .
Explanation :-
The mass by mass % is given as follows:-
Mass by mass % of a solution =
[ ( mass of solute / ( mass of solution ) ] × 100
Here, mass of solute is 110 g
So, the mass of solution is 550 g
Therefore , mass by mass % of solution =
( 110 × 100 ) / 550 g
= 20 % ( proved )
.....i hope it helps you
===========================
mark me as a brainlist.
The concentration of solution is 20% .
Explanation :-
The mass by mass % is given as follows:-
Mass by mass % of a solution =
[ ( mass of solute / ( mass of solution ) ] × 100
Here, mass of solute is 110 g
So, the mass of solution is 550 g
Therefore , mass by mass % of solution =
( 110 × 100 ) / 550 g
= 20 % ( proved )
.....i hope it helps you
===========================
mark me as a brainlist.
Similar questions