Question

If 1111=R, 2222=T, 3333=E, 4444=N Then 5555=?

Answer 1

The logic followed here is determining the last letter of the number obtained on adding all the digits.1111 = 1+1+1+1 = FOUR = R2222 = 2+2+2+2 = EIGHT = T 3333 = 3+3+3+3 = TWELVE = E4444 = 4+4+4+4 = SIXTEEN = N5555 = 5+5+5+5 = TWENTY = Y

Answer 2

Given:

• Some codes are given 1111=R, 2222=T, 3333=E, 4444=N

To Find:

• We have to find the code for 5555=?

Solution:

• First add the all digits of the number.
• After this write that sum in English and last letter of that English word is the code for that given number.

   ⇒      1111 = 1+ 1+ 1+ 1  =  FOUR = R

   ⇒      2222= 2+ 2+ 2+ 2 =   EIGHT = T

   ⇒      3333  = 3+ 3+ 3+ 3   =   TWELVE = E

   ⇒      4444  =   4+ 4+ 4+ 4  = SIXTEEN = N

In the same way code for 5555 is

   ⇒      5555= 5+ 5+ 5+ 5   = TWENTY  = Y

Thus, The code for 5555 = Y