If 1111th term of an AP is 2222 and 2222th term ofthe AP is 1111 then the value of 3333th term of theAP is(A)0(B)1111(C)2222(D)3333
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Answer:
= 0
Step-by-step explanation:
2222 nd Term = a + 2221 d = 1111
1111 st Term = a + 1110 d = 2222
by solving, 1111 d = - 1111
so, d = - 1
a = 3332
3333 rd Term = a + 3332 d
= 3332 + 3332 × ( -1 )
= 3332 - 3332
= 0
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