Question

If 1111th term of an AP is 2222 and 2222th term ofthe AP is 1111 then the value of 3333th term of theAP is(A)0(B)1111(C)2222(D)3333​

Answer 1

Answer:

= 0

Step-by-step explanation:

2222 nd Term = a + 2221 d = 1111

1111 st Term = a + 1110 d = 2222

by solving, 1111 d = - 1111

so, d = - 1

a = 3332

3333 rd Term = a + 3332 d

= 3332 + 3332 × ( -1 )

= 3332 - 3332

= 0