if 112 cm^3 of hydrogen sulphide is mixed with 120 cm^3 of chlorine at STP. what is the mass of sulphur formed according following equation
H2S + Cl2 - 2HCl + S
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Answer: 0.112 L of H2S will produce 32/22.4 x 0.112 = 0.16g of Sulfur.
Explanation:
if 112 cm3 of hydrogen sulphate is mixed with 120 cm3 of chlorine at STP, what is the mass of sulphur formed? H2 S + CL2 - 2HCL + S. When 22.4L of H2S reacts with 22.4L of Cl2 it produce 32 g Sulphur. 0.112 L of H2S will produce 32/22.4 x 0.112 = 0.16g of Sulfur.
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