if 112 g of fe combines with 48 g of o2 how much fe2o3 is formed??
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Amount of iron oxide formed when 112 g of Fe reacts with 24g of O2 is 108 grams. So 2 moles of iron react with 1 mole of oxygen to give 2 moles of FeO. That is 112 g of iron reacts with 32 g of oxygen but since oxygen is 24 grams as given hence oxygen is limiting reagent.
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Answer:
24 grams is answer
Explanation:
it is easy
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