Question

if 119C33 is divided by 5 then the remainder is (A) 1 (B)2 (C)3 (D)4

Answer 1

Answer:

C(3)

Step-by-step explanation:

Answer 2

Given:

119C33 is divided by 5.

To find:

Remainder when 119C33 is divided by 5.

Solution:

1) If the unit digit of any number is 0 or 5 then the number is completely divisible by the 5 it means that number gives remainder 0.

2) The given number is 119C33 which is nCr so the number will be given by

• n!/(n-r)!r!

• 119!/(119-33)!33!

• 119!/86!33!

• 119×118×117............87/33×32×31........1

• 264987608114625679810381761543

3)In the obtained number the unit digit is 3 which is less than 5 so the remainder will be the unit digit of the number.

The Remainder when 119C33 is divided by 5 is 3