Question

If ¹¹pr= 110 then the value of r is:​

Answer 1

Answer:

this is your solution for the following information

Answer 2

Value of r is 2.

Given:

• $^{11}P_r=110$

To find:

• The value of r.

Solution

Formula to be used:

$\bf ^nP_r=\frac{n!}{(n-r)!}$

Step 1:

Here,

n= 11

Put the formula in the equation.

$^{11}P_r=110$

$\frac{11!}{(11-r)!}=110$

Step 2:

Solve for r.

$\frac{11\times 10\times 9!}{(11-r)!}=11\times 10$

or

$\frac{9!}{(11-r)!}=1$

or

$9!=(11-r)!$

If value of r = 2, then only the above written equation will satisfy.

$9!=(11-2)!$

or

$9!=9!$

Thus,

Value of r is 2.

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