Question

If 12.0 L of H2 and 8.0 L of O2 are allowed to react The O2 left unreacted will be??
DO EXPLAIN IT AS WELL ...​

Answer 1

The reaction is H

2

+

2

1

O

2

→H

2

O.

At STP conditions, one mole of any gas will occupy 22.4 L.

12.0 L of hydrogen and 8.0 L of oxygen will correspond to

22.4

12.0

=0.54 moles and

22.4

8.0

=0.36 moles respectively.

One mole of hydrogen reacts with half mole of oxygen.

Hence, 0.54 moles of hydrogen will react with 0.27 moles of oxygen.

Hence, the number of moles of oxygen unreacted will be 0.36−0.27=0.09 moles.

The volume of oxygen unreacted will be 0.09×22.4=2.0 L.

Hence, option D is correct