Math, asked by pushpasidaps2, 10 months ago

If ∅=12/13, Evaluate: 2sin∅cos∅/cos²∅-sin²∅

Answers

Answered by amreshsingh827157484

2

Answer:

sin2θ−cos2θ2sinθcosθ×1tan2θ. =sin2θ−1+sin2θ2sinθcosθ×cos2θsin2θ. =2sin2θ− 12sin3θ×cosθ. =2sin2θ−12sin3θ×√1−sin2θ.

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