If (12 + 22 + 32 + .... + x?)= X(X+1)(2x +1)
6
then the value of (12 + 32 + 52 + ... + 192) is
(a) 1330
() 2100
(c) 2485
(d) 2500
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Answer:
1330 is the value of (12+32+52+72+92+112+132+152+172+192)
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