if 12.25m of an iron rod weight 49 kg. what will be the weight of the 7.75m of the saame rod
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it can be solved as
weight of 12.25m. = 49kg
weight of 1m road = 49/12.25
=4kg
weight of 7.75m road = 4×7.75
=31kg
hence,
weight is 31kg
Mark it BRAINLIEST
weight of 12.25m. = 49kg
weight of 1m road = 49/12.25
=4kg
weight of 7.75m road = 4×7.75
=31kg
hence,
weight is 31kg
Mark it BRAINLIEST
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