Question

If (−12)7 ÷ (3−5)−5 = . , find p and q

Answer 1

Answer:

Please Give Full Question

Answer 2

Answer:

The distance between two points is (x1,y1),(x2,y2) is √(x2-x1)^2+(y2-y2)^2

Now given points p(-2,-5),Q(3,7)

|PQ|=√(3-(-2))^2+(7-(-5))^2

=√ 5^2+12^2

=√25+144

=√169

=√(13^2)

=13

The distance between two points is 13