Question

If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is:
(a) $220 \bigg (\frac{1}{3}\bigg)^{12}$(b) $22\bigg (\frac{1}{3}\bigg )^{11}$(c) $\frac{55}{3}\bigg (\frac{2}{3}\bigg )^{11}$(d) $55\bigg (\frac{2}{3}\bigg )^{10}$

Answer 1

If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is:

(a) $220 \bigg (\frac{1}{3}\bigg)^{12}$(b) $22\bigg (\frac{1}{3}\bigg )^{11}$(c) $\frac{55}{3}\bigg (\frac{2}{3}\bigg )^{11}$(d) $55\bigg (\frac{2}{3}\bigg )^{10}$