If 12 is the smallest member of a Pythagorean triplet. Find the other two members?
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Step-by-step explanation:
2m = 12
m =12/2
m=6
m^2 -1 =6^2 -1
=36-1
=35
m^2+1
=6^2+1
=36+1
=37
12 ,35,37
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