If 12 persons are seated at round table, what is the probability that two particular persons sit together?
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Answer:
3/55
Step-by-step explanation:
Total probability=(12−1)!=11!
Desired probability=(10−1)!=9!
P=9! x 3!/11!
= 9! x 3!/11 x 10 x 9!
=3 x 2 x 1/11 x 10
= 3/55
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