Math, asked by trupti2786, 5 hours ago

if 12 sin Φ-5 cos Φ =0 then find the value of cot Φ , cosec Φ , and sec Φ​

Answers

Answered by guptaesha09
1

Answer:

cot Φ=12/5, cosec Φ=13/5 , and sec Φ=13/12

Answered by shivankg2004
1

Answer:

CotΦ = B/P = 12/5

CosecΦ = H/P = 13/5

SecΦ = H/B = 13/12

Step-by-step explanation:

12sinΦ-5cosΦ=0

12sinΦ=5cosΦ

Squaring Both Sides

144sin^{2}Φ = 25cos^{2}Φ

144sin^{2}Φ = 25(1-sin^{2}Φ)

144sin^{2}Φ=25-25sin^{2}Φ

169sin^{2}Φ=25

sin^{2}Φ=25/169

sinΦ=5/13

.: In a Triangle,

Perpendicular(P) = 5

Hypotenuse(H) = 13

Base(B) = \sqrt{H^{2} - P^{2} } = 12

CotΦ = B/P = 12/5

CosecΦ = H/P = 13/5

SecΦ = H/B = 13/12

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