Question

if 12 tan A = 5, calculate all other trigonometry ratios​

Answer 1

Answer:

sin A=p/h=5k/7k=5/7

cos A=b/h=12k/7k=12/7

tan A=p/b=5k/12k=5/12

cot A=12/5(reciprocal of tan)

sec A=7/12(reciprocal of cos)

cosec A=7/5(reciprocal of sin)

Step-by-step explanation:

12 tan A = 5

=>12×P/B=5

=>P/B=5/12

=>P/5=B/12=k(let)

therefore,p=5k and b=12k

now;

By pythagoras theorem

h^2=p^2+b^2 (^ stands for showing the power)

=>h^2=(5k)^2+(12k)^2

=49k^2

=>h=7k

now,

sin A=p/h=5k/7k=5/7

cos A=b/h=12k/7k=12/7

tan A=p/b=5k/12k=5/12

cot A=12/5(reciprocal of tan)

sec A=7/12(reciprocal of cos)

cosec A=7/5(reciprocal of sin)