if 12 term of am ap is -13 and the sum of first four term is 24 what is the sum of 10 term?
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Step-by-step explanation:
given: 12th term: t12= -13
we know that: t12= a+11d
where, a is first term and d is common difference....
so, a+11d= -13.........(1)
sum of first four terms= 24
we know sum formula: s= n(2a+(n-1)d)/2
where n= no. of terms
by substituting values in sum formula....we have..
24 = 4(2a+3d)/2
so, 2a+3d = 12.......(2)
by solving equation (1) amd (2) we get values as....
a= 9, d= -2
so, sum to ten terms formula: s= 10(2a+9d)/2
s= 10(18-18)/2
so, s= 0
therefore, sum of ten terms = 0
hope it helps you....
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