if 12 x +17y=48 and 17 x +12y=68,then what is the value of x-y
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12x+17y=48 ×12
17x+12y=68 ×17
144x+204y=57
289x+204y=1156
−145x=−580
x=4
substitute x value in the 1st equation
12×4+17y=48
48+17y=48
17y=0
then
x−y=4−0=4
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