If 120 g of NAOH were used to prepare 500 mL of solution, what would the concentration be
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M= w/W×v= 120/40×500/1000=120×1000/500×40=30
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Given:
120 grams of NaOH is used to prepare 500ml of a solution.
To Find:
The concentration of the solution.
Solution:
1. Molarity of a compound is defined as the number of moles of solute dissolved in 1L (1000ml) of the solution. It is given by the formula,
- Molarity(M) = (Weight of solute x 1000)/(GMW x V), where,
- GMW = Gram molecular weight,
- V = Volume of the solution in ml.
2. Substitute the values in the above formula,
=> Molecular weight of NaOH = 23 + 16 + 1 = 40,
=> Molarity = (120x1000)(40x500),
=> Molarity = (120)/(20),
=> Molarity = 6.
The molarity of the solution is 6M.
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