Chemistry, asked by khadijanisar828, 1 year ago

If 120 g of NAOH were used to prepare 500 mL of solution, what would the concentration be

Answers

Answered by adi45bro2up8kvb7
1
M= w/W×v= 120/40×500/1000=120×1000/500×40=30
Answered by Hansika4871
2

Given:

120 grams of NaOH is used to prepare 500ml of a solution.

To Find:

The concentration of the solution.

Solution:

1. Molarity of a compound is defined as the number of moles of solute dissolved in 1L (1000ml) of the solution. It is given by the formula,

  • Molarity(M) = (Weight of solute x 1000)/(GMW x V), where,
  • GMW = Gram molecular weight,
  • V = Volume of the solution in ml.

2. Substitute the values in the above formula,

=> Molecular weight of NaOH = 23 + 16 + 1 = 40,

=> Molarity = (120x1000)(40x500),

=> Molarity = (120)/(20),

=> Molarity = 6.

The molarity of the solution is 6M.

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