If 120 g of urea (NH2CONH2) is dissolve in 1000 g of H2O. Find molarity if density of solution is 1.12 gram per millilitres
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Answer:
2 M
Explanation:
solute (urea) = 120g = 120/60 = 2 moles
solvent (h2o) = 1000g
solution = 120+1000= 1120g
vol = mass/density
= 1120/1.12
= 1000 ml = 1 L
Molarity = 2 / 1
= 2 M
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