Question

if 120g of propane is burnt in excess of oxygen , how many gram of water are formed​

Answer 1

Qᴜᴇsᴛɪᴏɴ:-

➨ɪғ 120ɢ ᴏғ ᴘʀᴏᴘᴀɴᴇ ɪs ʙᴜʀɴᴛ ɪɴ ᴇxᴄᴇss ᴏғ ᴏxʏɢᴇɴ,ʜᴏᴡ ᴍᴀɴʏ ɢʀᴀᴍ ᴏғ ᴡᴀᴛᴇʀ ᴀʀᴇ ғᴏʀᴍᴇᴅ?

Aɴsᴡᴇʀ:-

➨ɢɪᴠᴇɴ:-

120ɢ ᴏғ ᴘʀᴏᴘᴀɴᴇ ɪs ʙᴜʀɴᴛ ɪɴ ᴇxᴄᴇss ᴏғ ᴏxʏɢᴇɴ.

➨ᴛᴏ ғɪɴᴅ:-

ᴍᴀss ᴏғ ᴡᴀᴛᴇʀ

➨sᴏʟᴜᴛɪᴏɴ:-

ᴀᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ᴀᴠᴀɢᴀᴅʀᴏ's ʟᴀᴡ 1 ᴍᴏʟᴇ ᴏғ sᴜʙsᴛᴀɴᴄᴇ ᴏᴄᴄᴜᴘɪᴇs 22.4ʟ ᴀᴛ sᴛᴘ.

ᴀᴠᴀɢᴀᴅʀᴏ's ɴᴜᴍʙᴇʀ=6.023×10²³ ᴘᴀʀᴛɪᴄʟᴇ.

ɴᴜᴍʙᴇʀ ᴏғ ᴍᴏʟᴇs=ɢɪᴠᴇɴ ᴍᴀss/ᴍᴏʟᴀʀ ᴍᴀss

= 120ɢ/44ɢ/ᴍᴏʟ

=2.7ᴍᴏʟ

sᴛɪᴏᴄʜᴏᴍᴇᴛʀʏ:-

1 ᴍᴏʟᴇ ᴏғ ᴘʀᴏᴘᴀɴᴇ=4 ᴍᴏʟᴇs ᴏғ ᴡᴀᴛᴇʀ

2.7 ᴍᴏʟᴇ ᴏғ ᴘʀᴏᴘᴀɴᴇ=4×2.7ᴍᴏʟᴇs ᴏғ ᴡᴀᴛᴇʀ

2.7 ᴍᴏʟᴇ ᴏғ ᴘʀᴏᴘᴀɴᴇ=10.8ᴍᴏʟᴇ ᴏғ ᴡᴀᴛᴇʀ

ᴍᴀss ᴏғ ᴡᴀᴛᴇʀ=ᴍᴏʟᴇ ×ᴍᴏʟᴀʀ ᴍᴀss

= 10.8×18

=194.4ɢ

sᴏ ᴍᴀss ᴏғ ᴡᴀᴛᴇʀ ɪs 194.4ɢ.

ᴀɴᴅ ᴀʟʟ ᴡᴇ ᴀʀᴇ ᴅᴏɴᴇ✔️

ʜᴏᴘᴇ ɪᴛs ʜᴇʟᴘs ᴜʜ❣️

Answer 2

$hello$

194 g of water is produced if 120 gram of propane is burnt in excess of oxygen

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023 × 10 ²³of particles.

To calculate the moles, we use the equation:

No. of moles = Given mass /Molar mass = 120g / 44g or mol = 2.7 mole

C3H8 + 5O2 + 4 H20

According to stoichiometry:

1 mole of propane produces = 4 moles of water

2.7 moles of propane produce= 4/1 × 2.7 = 10.8 moles of water

Mass of water = moles × molar mass = 10.8 mol × 18g / mol = 194g

I hope my answer helps you....✌

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