if 124=q×5+r, then find the possible value of r
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Given : 124=q×5+r
To Find : the possible value of r
Solution:
Dividend = Divisor x Quotient + remainder
Stop the division if remainder is zero or degree of remainder is less than quotient
Euclid's Division Lemma
a=bq+r
a = dividend
b = divisor
q = quotient
r = remainder
0 ≤ r < b
124 = q × 5 + r
Hence r < 5
Possible values of r are 0 , 1 , 2 , 3 , 4
On performing Division actual value of r is 4
124 = 24 * 5 + 4
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