if 125 drops charged to 200V each coalesce, what will be the potential of the big drop? what is the ratio of energy of the bigger drop to the initial energy of the drops?
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Answered by
0
Answer:
Answer
Correct option is
B
V=
4πε
1
r
q
=(200)
Potential on small drops =
4πε
1
(
r
q
)
Volume of 125 small drops =125(
r
q
×
1πε
1
)
big volume = 125×small volume
R=5r
V
′
=
4πε
1
(
R
Q
)
V
′
=
4πε
1
(
5r
125q
)
V=
4πε
1
r
q
=(200)
Explanation:
it's is right answer hii
Answered by
4
Answer:
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Explanation:
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❤️ Take care & love you ishu ❤️
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