Question

if 12c-2(c+1)=8c+22,find the value of c​

Answer 1

Answer:

$\sqrt{x} \\ \leq \geq \geq x^{2} \neq \sqrt{x} \sqrt[n]{x} \sqrt[n]{x} \frac{x}{y} \frac{x}{y}$

Step-by-step explanation:

Answer 2

Answer:

c=10

$12c - 2(c + 1) = 8c + 22 \\ 12c - 2c + 2 = 8c + 22 \\ 10c + 2 = 8c + 22 \\ 10c - 8c = 22 - 2 \\ 2c = 20 \\ c = 10$