If 12th term in AP is -13 and sum of the first four term is 24 what is the sum of the first ten term
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a12 is given -13
i. e we can also write it as a+11d =-13
so taking value of a =-13+11d
now second condition is given that
Sn =24
we can also write it as
n/2(2a + n-1)d =24
n=4 given
so, 4/2(2*(-13+11d)+ 3d )
therefore 2(-26+22d +3d )
so, 2(-26+15d ) =24
-26+15d =12
15d = 12+26
d =38/15
hope it helps u can further solve and if need help than comment or inbox me
i. e we can also write it as a+11d =-13
so taking value of a =-13+11d
now second condition is given that
Sn =24
we can also write it as
n/2(2a + n-1)d =24
n=4 given
so, 4/2(2*(-13+11d)+ 3d )
therefore 2(-26+22d +3d )
so, 2(-26+15d ) =24
-26+15d =12
15d = 12+26
d =38/15
hope it helps u can further solve and if need help than comment or inbox me
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