If 12th term of the ap is -13 and sum of its first four term is 24.3 and sum of its first four term is 24. what is sum of first ten terms?
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T12=-13 a+11d=-13 a=-13-11d
s4=4/2(2*a+(4-1)*d)
24=2(2a+3d)
24/2=2a+3d
12=2a+3d
12=2(-13-11d)+3d
12=-26-22d+3d
12+26=-19d
38/19=-d
-2=d
a=-13-11d
a=-13-11*-2
a=-13+22
a=9
s10=10/2(2*9+(10-1)*-2)
=5(18-18)
=5*0
s10 =0
I hope it will help you!!!!
s4=4/2(2*a+(4-1)*d)
24=2(2a+3d)
24/2=2a+3d
12=2a+3d
12=2(-13-11d)+3d
12=-26-22d+3d
12+26=-19d
38/19=-d
-2=d
a=-13-11d
a=-13-11*-2
a=-13+22
a=9
s10=10/2(2*9+(10-1)*-2)
=5(18-18)
=5*0
s10 =0
I hope it will help you!!!!
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4
Answer:
the answer will be 0.............. ok......
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