If 12x+ 17y=48 and 17x+12y=68,then what is the value of x-y ?
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Answered by
4
12x=48-17y
x=(48-17y)/2
17 (48-17y/2)+12y=68
816-289y+24y/2=68
816-289y+24y=136
-235y=-678
y=678/235=2.89
x=48-17 (2.89)/2=-0.57
Therefore,
-0.57-2.89=-3.46
I think its the answer...
x=(48-17y)/2
17 (48-17y/2)+12y=68
816-289y+24y/2=68
816-289y+24y=136
-235y=-678
y=678/235=2.89
x=48-17 (2.89)/2=-0.57
Therefore,
-0.57-2.89=-3.46
I think its the answer...
Answered by
4
-3.46 is the answer.
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