Question

If 13 15 17 18 and n are arranged in ascending order and their median and mean is equal then find the value of n

Answer 1

mean=63/4
media=16
n=4

Answer 2

Answer:

The numbers are 6, 8, 10, 12, 13 and x

The numbers are 6, 8, 10, 12, 13 and xn = 6

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)For median n = 6 (even)

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)For median n = 6 (even)Median = [(n/2)th term +( n/2 + 1)th term]/2

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)For median n = 6 (even)Median = [(n/2)th term +( n/2 + 1)th term]/2Median = (3rd term + 4th term)/2

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)For median n = 6 (even)Median = [(n/2)th term +( n/2 + 1)th term]/2Median = (3rd term + 4th term)/2= (10 + 12)/2

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)For median n = 6 (even)Median = [(n/2)th term +( n/2 + 1)th term]/2Median = (3rd term + 4th term)/2= (10 + 12)/2= 22/2 =11    …(2)

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)For median n = 6 (even)Median = [(n/2)th term +( n/2 + 1)th term]/2Median = (3rd term + 4th term)/2= (10 + 12)/2= 22/2 =11    …(2)From (1) and (2)(from question)

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)For median n = 6 (even)Median = [(n/2)th term +( n/2 + 1)th term]/2Median = (3rd term + 4th term)/2= (10 + 12)/2= 22/2 =11    …(2)From (1) and (2)(from question)Median = mean

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)For median n = 6 (even)Median = [(n/2)th term +( n/2 + 1)th term]/2Median = (3rd term + 4th term)/2= (10 + 12)/2= 22/2 =11    …(2)From (1) and (2)(from question)Median = mean11 = (49 + x)/6

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)For median n = 6 (even)Median = [(n/2)th term +( n/2 + 1)th term]/2Median = (3rd term + 4th term)/2= (10 + 12)/2= 22/2 =11    …(2)From (1) and (2)(from question)Median = mean11 = (49 + x)/6⇒ x = 66 – 49

The numbers are 6, 8, 10, 12, 13 and xn = 6Mean = (6 + 8 + 10 + 12 + 13 +x)/6Mean = (49 + x)/6       …(i)For median n = 6 (even)Median = [(n/2)th term +( n/2 + 1)th term]/2Median = (3rd term + 4th term)/2= (10 + 12)/2= 22/2 =11    …(2)From (1) and (2)(from question)Median = mean11 = (49 + x)/6⇒ x = 66 – 49⇒ x =17.