Question

If 1³ + 2³ + 3³ + ……+ K³ = 4356. Find the value of K​

Answer 1

3+8+27+k=4356

38+k=4356

k=4356-38

k=4318

my dear friend here is your answer

Answer 2

Answer :

Note : That k is a positive integer.

Note : That k is a positive integer.Given that

Note : That k is a positive integer.Given that1³ + 2³ + 3³ + ... + k³ =4356

Note : That k is a positive integer.Given that1³ + 2³ + 3³ + ... + k³ =4356= k(k+1) ²

Note : That k is a positive integer.Given that1³ + 2³ + 3³ + ... + k³ =4356= k(k+1) ² _____ = 4356 =6×6×11×11

Note : That k is a positive integer.Given that1³ + 2³ + 3³ + ... + k³ =4356= k(k+1) ² _____ = 4356 =6×6×11×11 2

Note : That k is a positive integer.Given that1³ + 2³ + 3³ + ... + k³ =4356= k(k+1) ² _____ = 4356 =6×6×11×11 2Taking square root , we get

Note : That k is a positive integer.Given that1³ + 2³ + 3³ + ... + k³ =4356= k(k+1) ² _____ = 4356 =6×6×11×11 2Taking square root , we get k(k + 1)

Note : That k is a positive integer.Given that1³ + 2³ + 3³ + ... + k³ =4356= k(k+1) ² _____ = 4356 =6×6×11×11 2Taking square root , we get k(k + 1) _____ = 66

Note : That k is a positive integer.Given that1³ + 2³ + 3³ + ... + k³ =4356= k(k+1) ² _____ = 4356 =6×6×11×11 2Taking square root , we get k(k + 1) _____ = 66 2

Note : That k is a positive integer.Given that1³ + 2³ + 3³ + ... + k³ =4356= k(k+1) ² _____ = 4356 =6×6×11×11 2Taking square root , we get k(k + 1) _____ = 66 2= k² + k - 132 = 0 (k+12) (k-11) = 0

Note : That k is a positive integer.Given that1³ + 2³ + 3³ + ... + k³ =4356= k(k+1) ² _____ = 4356 =6×6×11×11 2Taking square root , we get k(k + 1) _____ = 66 2= k² + k - 132 = 0 (k+12) (k-11) = 0Thus, k = 11 , since k is positive