Math, asked by ShrushteeNagarikar, 8 months ago

If
13√25−3√5+1=A3√25+B3√5+C

Then, A + B + C=?​

Answers

Answered by amitnrw
0

Given :  13√25−3√5+1=A3√25+B3√5+C

To Find : A + B + C

Solution:

13√25−3√5+1=A3√25+B3√5+C

13√25 = A3√25

=> 13 = A3

=> A = 13/3

−3√5 = B3√5

=> B = - 1

1 = C

=> C = 1

A + B + C =  13/3  - 1  + 1  

= 13/3

A + B + C =  13/3

Learn more:

13√25−3√5+1=A3√25+B3√5+C

https://brainly.in/question/23306291

If a 2 +b 2 +c 2 =70, ab+bc+ca=37. find abc?

https://brainly.in/question/402053

ab+bc+ac=0 find the value of 1/a2

https://brainly.in/question/1221858

Similar questions