If 13−4i13−4i is a root of ax2+bx+c=0,(a,b,c∈R,a≠0)ax2+bx+c=0,(a,b,c∈R,a≠0) , then
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if one root of the quadratic
ax^2+bx+c=0 is 3-4i then 31 a+b+c=(A)0
(B)2a (C) 2b (D) 2c.
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