Question

if √13-a√10 = 2√2+√5,then a²+a^-1 is -​

Answer 1

Answer:

√13-a√10 = 2√2+√5,then a²+a^-1 is -??

Step-by-step explanation:

√13-a√10 = 2√2+√5,then a²+a^-1 is -???

Answer 2

$\sqrt{13} -a \sqrt{10} = 2 \sqrt{2} + \sqrt{5} \\ \\ a = - \bigg\{ \frac{2 \sqrt{2} + \sqrt{5} - \sqrt{13} }{ \sqrt{10} } \bigg \} \\ \\ a = - \bigg\{\frac{2 \sqrt{2} + \sqrt{5} - \sqrt{13} }{ \sqrt{10} } \times \frac{ \sqrt{10} }{ \sqrt{10} } \bigg \} \\ \\ a = - \bigg\{ \frac{2 \sqrt{2} + \sqrt{5} - \sqrt{13} \big( \sqrt{10} \big)}{ { {( \sqrt{10} )}^{2} } } \bigg \} \\ \\ a = - \bigg\{ \frac{2 \sqrt{20} + \sqrt{50} - \sqrt{130} }{10} \bigg \} \\ \\ a = - \bigg\{ \frac{4 \sqrt{5} + 5 \sqrt{2} - \sqrt{130} }{10} \bigg \} \\ \\ \pink{a = \bigg\{ \frac{ \sqrt{130} - 5 \sqrt{2} - 4 \sqrt{5} }{10} \bigg \}}$