If (13-a√10)^2=√8+√5 then find a
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(13-a√10)^2=√8+√5
root 2 and root 10 is been cancled
13-a*10=√13
-a*10=√13-13
-10a=√13-13
a=√13-13%10
a=√13-0.7
a=√12.3
❤so the value of 'a' is=√12.3
root 2 and root 10 is been cancled
13-a*10=√13
-a*10=√13-13
-10a=√13-13
a=√13-13%10
a=√13-0.7
a=√12.3
❤so the value of 'a' is=√12.3
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