Question

if 13 sin=12 find sec^2Q-tan^2Q​

Answer 1

Answer:

1

hey mate see here

Step-by-step explanation:

13 sin = 12

> sin theta = 12/13

by using Pythagoras we get base = 5

so we got base = 5

height=12

hypotenuse=13

so now put this values in sec^2Q-tan^2Q

you will get ANSWER = 1

Answer 2

Answer:

what is this...............

Step-by-step explanation:

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