Question

if 13 sin A = 12
find sec A - tan A

Answer 1

Answer:

13sinA=12

sinA=12/13

sin2A+cos2A=1

(12/13)2+cos2A=1

144/169+cos2A=1

cos2A=1-144/169

cos2A=169-144/169

=25/169

cosA=5/13....taking so. root

secA=1/cosA

=1/5/13=13/5

secA=13/5

tanA=sinA/cosA

=12/13/25/13=12/25

tanA=12/25

secA-tanA=13/5-12/25=65-12/25=53/25

secA-tanA=53/25.