If 13 sin A = 12
find sec A-tan A.
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Answer:
sin a=12/13
using Pythagoras theorem
in triangle abc
(ab) square+(bc) square=(ac) square
(ab) square=(13) square-(12) square
= 169-144
=25
ab=5
secA=13/5
tan A=p/b
=12/5
=13/5-12/5
=1/5
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